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The rate law for substitution of 2-bromobutane with HO--- in 75% ethanol 25% water at 30 degrees centigrade is Rate = 3.2 x 10---5[2-bromobutane][HO---] 1.5 x 10---6[2-bromobutane] What % of reaction takes place by SN2 when a) [HO---] = 1 M b) [HO---] = 0.001 M

The rate law for substitution of 2-bromobutane with HO--- in 75% ethanol 25% water at 30 degrees centigrade is
 
 
Rate = 3.2 x 10---5[2-bromobutane][HO---] 1.5 x 10---6[2-bromobutane]
 
 
What % of reaction takes place by SN2 when
 
 
a) [HO---] = 1 M
 
 
b) [HO---] = 0.001 M

Grade:12th pass

1 Answers

Yuvraj Singh
askIITians Faculty 75 Points
17 days ago
The rate law for substitution of 2-bromobutane with HO --- in 75% ethanol 25% water at 30 degrees centigrade is Rate = 3.2 x 10 ---5 [2-bromobutane][HO --- ] 1.5 x 10 ---6 [2-bromobutane]

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