molecular mass of magnesium bicarbonate = 146
no. of moles = given weight/moecular weight
= 14.6/146 =0.1 …...............(1)
here, no. of moles of oxygen in magnesium bicarbonate = 16*3*2/16 = 6 …..............(2)
[from (1) and (2) ],
0.1*6*NA =0.6 NA
So, the number of oxygen atoms present in 14.6 g of magnesium bicarbonate is 0.6 NA.