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The increasing order of boiling points of the below mentioned alcohols is (I) 1,2-dihydroxybenzene (II) 1,3-dihydroxybenzene (III) 1,4-dihydroxybenzene (IV) Hydroxybenzene

The increasing order of boiling points of the below mentioned alcohols is
(I) 1,2-dihydroxybenzene
(II) 1,3-dihydroxybenzene
(III) 1,4-dihydroxybenzene
(IV) Hydroxybenzene

Grade:12th pass

1 Answers

Kevin Nash
askIITians Faculty 332 Points
9 years ago

(d) Among the given compounds, hydroxybenzene (IV) has least molar mass and therefore posses least boiling point. Among the three isomeric dihydroxybenzenes, 1,2- dihydroxybenzene (I) forms intramolecural H-bonding with the result it will not form intermolecular H-bonding leading to lowest boiling point. On the other hand 1,3-dihydroxybenzene (II) and 1,4-dihyroxybenzene (III)do not undergo chelation, hence they will involve extensive intermolecular H-bonding leading to higher boiling point. Further intermolecular hydrogen bonding is stronger in the p-isomer than the m-isomer hence former has highest b.p. Thus the deacreasing order of boiling points is III > II > I >IV.

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