Grade 11Organic Chemistry

The amount of Zinc required to produce 1.12 ml of H2 at STP on treatment with dilute HCL will be? plz ansr soon Thanks in advance

Shubhnit Singh

10 Years agoGrade 11

3 Answers

Beenu Mathew

10 Years ago

HI,

Zn + 2HCl -----> H₂ + ZnCl₂

_Now it is given in the question that 1.12 ml at STP is formed

so????

look at the equation carefully

you will see

1 mole of Zn gives you 1 mole of H₂

so ...yea its on this basis we will be solving the rest of this question

1.12 ml of H₂ is how many moles

1.12/22.4 = .05 moles

so 0.05 moles of Zn is required

0.05 * 65.4 = 3.27g (by the way 65.4g is the molar mass of Zn.,,,,checked it on google ;) )

THANKS!!

BEST OF LUCK

CHEERS!!

Akash Biswas

9 Years ago

Zn + 2HCl --» ZnCl2 + H21 Mole of zinc reacts to produce 1 mole of hydrogen gas ..So 1.12 ml of hydrogen gas contains 1.12 ml/22400 ml = 0.5* 10 ^ -4Thus 0.5* 10 ^ -4 mole if hydrogen gas is obtained from 0.5* 10 ^ -4 mole of Zinc So amount of zinc required to produce 1.12 ml of hydrogen gas is Molecular weight of Zn*0.5* 10 ^ -4=65.38*0.5* 10 ^ -4= 32.5 * 10 ^ -4 g