Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

the ammonia evolved from the treatment of 0.3g of an organic compound for the estimation of nitrogen was passed in 100ml of 0.1 M sulphuric acid. The excess of acid required 20ml of 0.5 M sodium h hydroxide solution for complete neutralization. The organic compound is a) acetamide b) thiourea c) urea d) benzamide ​

the ammonia evolved from the treatment of 0.3g of an organic compound for the estimation of nitrogen was passed in 100ml of 0.1 M sulphuric acid. The excess of acid required 20ml of 0.5 M sodium h hydroxide solution for complete neutralization. The organic compound is a) acetamide b) thiourea c) urea d) benzamide

Grade:12th pass

1 Answers

Vikas TU
14149 Points
4 years ago
NaOH mmoles that reacted with excess acid = 20*0.5 = 10 mm
excess acid mm => {from mole 2 conceptt}
moles x valence factor = cinstant.
Therefore,
nH2SO4 x 2 = 10 x  1
mm of H2SO4  = 5 mm.
Now H2SO4 that reacted with ammonia in actual is
=> 0.1 x 100 – 5
=> 10 –  5 
=> 5 mm.
The reaction is:
2NH3       +      H2SO4         --------->             (NH4)2SO4
From 5 mm of H2SO4 NH3 mmoles are => 5 x 2 =  > 10 mm.
mm of NH3 = 10 mm.
Applying POAC
For each option and cross checking,
Thaking Urea first,
for Nitrogen atom.
2 x moles = 10 x 1
moles =  5 mm.
For 0.3 gm,
MOlar masss = 0.3/0.005 => 60 g
Thus urea is the organic compound.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free