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sir, Thanks for the Lucas test explanation in equation format. Kindly provide ,how do i calculate Coordination No + Oxidation No from basics,How do i name it in IUPAC Naming using Roman Letter. K 4 [Fe(CN) 6 ] and [Cu(NH 3 ) 4 ]SO 4 vincent

sir,
 
Thanks for the Lucas test explanation in equation format.
Kindly provide ,how do i calculate Coordination No + Oxidation No from basics,How do i name it in IUPAC Naming using Roman Letter.
 
K4[Fe(CN)6] and [Cu(NH3)4]SO4
vincent
 

Grade:12

1 Answers

Rajeev
35 Points
5 years ago
coordination number is calculated by adding the charge of the metal ion ligand and the other ions out side the squre brackets .
K4FeCN6
4 k+ ie +4.  Fe x.   6 CN-  -6 put the oxidation state of Fe as x
ADDING +4+x-6=0
x=+2
so oxidation state of Fe is +2.
there are six CN- mono dentate ligands so coordination number 6
in the second question NH3 is nuetral has no charge but can donate one electron pair so monodentate so four  NH3 is there so coordination number 4.
adding the charges Cu x NH3=0 and SO4 =-2
adding x+0-2=0
x=+2
oxidation number of Cu is +2

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