Sir, Thanks for the Answer but little confusion, i.e you had subtitute -6 and -2 directly in the equation, could you please guide me the procedure how do i find this –ve Negative or +ve positive charge. K 4 [Fe(CN) 6 ] and [Cu(NH 3 ) 4 ]SO 4 CN = -6 SO4 = -2 vincent

Question

Arun · Answer

Dear student CN has – 1 charge while SO4 has – 2. I should be known by lewis structure. Hope it helps Regards Arun

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Sir, Thanks for the Answer but little confusion, i.e you had subtitute -6 and -2 directly in the equation, could you please guide me the procedure how do i find this –ve Negative or +ve positive charge. K 4 [Fe(CN) 6 ] and [Cu(NH 3 ) 4 ]SO 4 CN = -6 SO4 = -2 vincent

Sir, Thanks for the Answer but little confusion, i.e you had subtitute -6 and -2 directly in the equation,
could you please guide me the procedure how do i find this –ve Negative or +ve positive charge.
K₄[Fe(CN)₆] and [Cu(NH₃)₄]SO₄

CN = -6
SO4 = -2
vincent

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Sir, Thanks for the Answer but little confusion, i.e you had subtitute -6 and -2 directly in the equation, could you please guide me the procedure how do i find this –ve Negative or +ve positive charge. K 4 [Fe(CN) 6 ] and [Cu(NH 3 ) 4 ]SO 4 CN = -6 SO4 = -2 vincent

Sir, Thanks for the Answer but little confusion, i.e you had subtitute -6 and -2 directly in the equation,could you please guide me the procedure how do i find this –ve Negative or +ve positive charge.K4[Fe(CN)6] and [Cu(NH3)4]SO4 CN = -6SO4 = -2vincent

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Sir, Thanks for the Answer but little confusion, i.e you had subtitute -6 and -2 directly in the equation,
could you please guide me the procedure how do i find this –ve Negative or +ve positive charge.
K₄[Fe(CN)₆] and [Cu(NH₃)₄]SO₄

CN = -6
SO4 = -2
vincent