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Grade 12th passGeneral Physics

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Profile image of anila
9 Years agoGrade 12th pass
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1 Answer

Profile image of Saurabh Koranglekar
6 Years ago
965Ampere of current will be equal to0.01F(1F= 96500amp, so 956amp will be 0.01F)

Therefore,
Mass of Ag deposited will be= 108* 0.01
=1.08grams