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q a5ppppppllllllppppppppppppppppppppppppppppleaseppppppllllllppppppppppppppppppppppppppppleas

q a5ppppppllllllppppppppppppppppppppppppppppleaseppppppllllllppppppppppppppppppppppppppppleas

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Grade:12th pass

2 Answers

Naveen Kumar
36 Points
6 years ago
Please fofofofofofofororororororor whwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhwhatatatatatatatatatatatatatat. ?
Naveen Kumar
36 Points
6 years ago
Lets number the carbon from Left top C atom as 1 and move anticlockwise .
 
Hybridisation for each C atom is 
C1 sp2 , C2 sp2, C3 sp2 , C4 sp2 ,
C5 sp3 , C6 sp3 , C7 sp2 , C8 sp2, C9 sp3 , C10 sp3
 
Now if we lable hybridisation on fig. And counting no. of sigma bonds between sp2 and sp2 C atoms.
 
We get 4 sp2 - sp2 sigma bonds.

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