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Plz. ans. attached question.Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz.

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Grade:12th Pass

3 Answers

Arun
25750 Points
6 years ago
Dear Parth
 
The formula C4H8 stands for 4 structural isomers.
1. Butene-1, CH2=CH-CH2-CH3
2. Butene-2, CH3-CH=CH-CH3
3. 2-Methyl propene, CH3-C(CH3)=CH2
4. Cyclobutane ( 4-membered ring with a CH2 group at each corner).
But butene-2 exists in both cis and trans forms (2 geometrical isomers).
Regards
Arun (askIITians forum expert)
Parth Verma
49 Points
6 years ago
Respected expert Mr. Arun, my ans. is coming 6. One aditional I am getting which is 1-methylcyclopropane. Whether I am wright?
Harish
82 Points
6 years ago
Hello Parth,
 
The answer to your query is given below :
 
Since it is an alkene, therefore it will have one degree of unsaturation. Therefore, the following structures can be drawn :
 
​1).  But-1-ene
2).  cis but-2-ene
3).  trans but-2-ene
4).  2-Methylprop-1-ene
5).  cyclobutane
6).  1-Methylcyclopropane
 
Hope this clears your doubt !

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