Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Plez explain this graph with blackbody and plank`s quantum theory

Plez explain this graph with blackbody and plank`s quantum theory

Question Image
Grade:11

1 Answers

Umakant biswal
5359 Points
5 years ago
@ SAKSHI 
WHat u need to understand is that as far as planks quantum theory is concerned , it tells that if an light of suitable frequency and wavelength are incident in a metal plate , then it will emit the electrons due to absorption of quanta , in which quanta refers to the energy packets . 
and ACC TO HIM its deviated by some charecter like intensity , wavelength , frequency , of incident light . 
acc to your graph , if the intensity will be increased then it will obviously increase the wavelength at certain time T2 . 
if intensity will be increased then more no of photon particle will enter inside the metal and collide with the existing electrons in the metal . 
and once its collision per second will be increased then more no of electrons will coming out . 
that will increase the wavelength obviously . 
and if u are concerned with blackbody radiation , then its a radiation which will be emitted by an opeque object , and acc to this graph ,
consider the metal to be an opeque object and once light of suitable frequency incident in it , it will start producing radiation , and if intensity will be increased then the radiation will be increased . 
and acc to the rule , radiation is directly proportional to wavelength . 
so, wavelegth will be increased once radiation increased , 
HOPE IT CLEARS YOUR DOUBT 
IF ANY MORE , THEN LET ME KNOW .. 
ALL THE BEST ..
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free