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Grade: 12
        
Please solve this question. Also mention tge general rule for solvimg such problems 
Thankyou. 
10 months ago

Answers : (1)

Arun
22540 Points
							
 

Let us start back wards!

4) NH2-NH2 Here n is sp3 hybridised, hence it is non planar

3) (SiH3)3N Here the lone pair of N has been absorbed by the vacant d- orbital. Hence it is sp2 hybridised and planar.

2) F2B-C=C=C-BF2

BF2-C= is planar and =C-BF2 is also planar. But concentrate on central C atom!. Say it uses x axis for sigma  bonds. Then it uses Py and Pz for pi bonds which are inclined at 90*. Hence the 2 triagonal planar structures  of BF2C are inclined at 90*.

1)F2C=C=CF2    Same as 2nd.  

10 months ago
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