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Number of dimerisation product of given reaction :CH2=CH-CH=CH-CH2-Cl + CH3-CH2-Cl (sodium in dry ether i.e. Wurtz reaction)-------> ————>

Number of dimerisation product of given reaction :CH2=CH-CH=CH-CH2-Cl + CH3-CH2-Cl (sodium in dry ether i.e. Wurtz reaction)-------> ————>

Grade:12th pass

1 Answers

Vikas TU
14149 Points
5 years ago
Since the given reaction is a wurtz reaction there will be free radical mechanism which can lead to multiple products.If we consider free radical and double bond resonance we will get two possible structures for the first reactant so the number of products will be 2.This is the count without considering the geometrical resonance.

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