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Grade: 12
        
lim-(x-? p/2)??tan2x/(x-p/2)?
4 years ago

Answers : (1)

Rinkoo Gupta
askIITians Faculty
80 Points
							lim x->pi/2 tan2x/(x-pi/2)
on putting values we get tan(pi)/(pi-pi)=0/0
so by sing L'Hospital rule,we get
limx->pi/2 2sec2(2x)/1
=2sec2(pi)=2(-1)2=2 Ans.
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
4 years ago
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