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Grade: 11
        
in the preparation of alkanes by decarboxylation of sodium salts, why NaOH behave as an acid?
2 years ago

Answers : (1)

Arun
23544 Points
							

 

Dear student

It involves the treatment of sodiumsalt of carboxylic acids with soda lime (NaOH and CaO in the ratio 3 : 1).

 

The alkane fanned has one carbon less than the sodium salt of carboxylic acid.

In this reaction CaO does not participate in the reaction but helps in fusion of the reaction mixture.

(b) Electrolytic Decarboxylation. This reaction is also called Kolbe’s reaction. In this reaction an aqueous solution of sodium or potassium salt of a carboxylic acid is electrolysed. Alkane is formed at anode.

 

Regards

Arun (askIITians forum expert)

2 years ago
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