In the oxidative cleavage of methyl propyl ketone, we get Propanoic acid and ethanoic acid. How is this in any ways related to poppof’s rule since both the products have the same group attached to them?

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BIKRAM · Answer

According to poppof’s rule during oxidative cleavage of unsymmetrical ketone, keto group remains with methyl group(small part) . Ethanoic acid is coming from ketomethyl part and propanoic acid is coming from propyl part .

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In the oxidative cleavage of methyl propyl ketone, we get Propanoic acid and ethanoic acid. How is this in any ways related to poppof’s rule since both the products have the same group attached to them?

In the oxidative cleavage of methyl propyl ketone, we get Propanoic acid and ethanoic acid. How is this in any ways related to poppof’s rule since both the products have the same group attached to them?

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In the oxidative cleavage of methyl propyl ketone, we get Propanoic acid and ethanoic acid. How is this in any ways related to poppof’s rule since both the products have the same group attached to them?

In the oxidative cleavage of methyl propyl ketone, we get Propanoic acid and ethanoic acid. How is this in any ways related to poppof’s rule since both the products have the same group attached to them?

1 Answers

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