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In question F write the decreasing order towards aromatic electrophilic substitution?

In question F write the decreasing order towards aromatic electrophilic substitution?

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Grade:12

1 Answers

Vikas TU
14149 Points
4 years ago
From left to right, the amount of electron donation into the ring (activating the ring towards EAS) decreases.
OH is a σ donor (its HOMO is a σbonding orbital), thereby activating the ring strongly.
CH3 donates via hyperconjugation (from its C−H bonds), thereby activating the ring weakly.
F is a decent π donor (filled  p nonbonding orbitals) but is a good EWG, thereby deactivating the ring weakly.
NO2 is a very strong EWG, thereby deactivating the ring strongly.
Therefore, from left to right, we have most to least reactive towards EAS.
 

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