Learn to Create a Robotic Device Using Arduino in the Free Webinar. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on Robotics (Block Chain) Learn to create a Robotic Device Using Arduino
30th Jan @ 5:00PM for Grade 1 to 10
(I posted this question many time but I not found any satisfactory answer.Please ,sir help me.This is a question of MS Chouhan .Please expalin in detail why we consider both the lone pairs on oxygen as it has only 1 pi orbital so it must have only 1 pair of pi electron after resonance also.Please explain in detail as I fed up after posting this same question many times Q-Calculate the number of pi electrons present in the following compound(see attachment)? Ans-10 (I posted this question many time but I not found any satisfactory answer.Please ,sir help me.This is a question of MS Chouhan .Please expalin in detail why we consider both the lone pairs on oxygen as it has only 1 pi orbital so it must have only 1 pair of pi electron after resonance also.Please explain in detail as I fed up after posting this same question many timesQ-Calculate the number of pi electrons present in the following compound(see attachment)?Ans-10
The answer can be explained using the concept of hybridisation.Electronic configuration of O atom is 1s22s22p4 now, there are 2 unpaired electrons in p orbital and one is paired. So what happen is that electrons of 2s and 2p combine to hybridize which let the electrons to act as pi electrons. and hence there are two lone pairs found on oxygen atom one on 2s and other on 2p.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -