Aabid Hussain
Last Activity: 8 Years ago
Hi Chinu,
There are three scenario that depends upon the numbers of double bond and the entities at the start and end of the chain (for example, H5C6, COOH).
But, considering the only one scene here
When a compound has ‘n’ number ofdouble bonds and ends of a given chain are different, the number of geometrical isomers = 2n
As in the given structure, numbers of double bonds are 2.
So, geometrical isomers will be 22= 4.