As the DU/DBE of C5H10 is 1.It can either be a ring or with one double bond.1. Cyclopentane2. Methylcyclobutane3. 1,2 Dimethylcyclopropane4. Ethylcyclopropane
4 isomers can be possible1) cyclopentane2) methylcyclobutane3) 1,2 dimethyl cycloprpane4) Ethylcyclopropane
Shiv
8 Years ago
5 isomers can be possible1) cyclopentane2) methylcyclobutane3) 1,2 dimethyl cycloprpane4) Ethylcyclopropane5)1,1-Dimethylcyclopropane
abc
8 Years ago
the correct answer is 7 isomers.
Sanmay
8 Years ago
The answer came to be seven as the isomers who are optically active have two enantiomers and there are 2 cyclic structures which are optically active so answer is seven...
Irwin sethi
7 Years ago
5 isomers are possible
1- cyclopentane
2- methyl cyclobutane
3- ethyl cyclopropane
4- 1,1dimethylcyclopropane
5- 1,2dimethylcyclopropane
Rishi Sharma
5 Years ago
Dear Student, Please find below the solution to your problem.
As the DU (degree of unsaturation for C5H10 is 1). It can either be a ring or with one double bonded. Since for cyclic compounds, The isomers are: Cyclopentane Methylcyclobutane 1,2-dimethylcyclopropane