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How ethyl magnesium bromide reacts with 2-butanone?? Which product is formed ?? Plz explain with mechanism....

How ethyl magnesium bromide reacts with 2-butanone?? Which product is formed ?? Plz explain with mechanism....

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1 Answers

Ankit
104 Points
6 years ago
2-butanone + CH3CH2MgBr = 3 methyl-3-pentanol... Ethyl Magnesium BROMIDE reacts with 2-butanone to form 3 methyl-3-pentanol...... The double bond of C and O in 2 butanone breaks and the CH3CH2 (ethyl group) from ethyl magnesium BROMIDE fulfills the space left after breakage of double bond.......... And after using H3O+ we get 3 METHYL -3-PENTANO E which is a tertiary alcohol....... Hope you understand the complete mechanism....

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