[Co(cl)2(NH3)4]^(+) ..... tetraammoniadichloridocobalt(|||) is a AB6L type of molecule , shape is octahedron. But how?? plz explain the hybridisation of the compound

Question

GAURAV SINGH · Answer

tetraammoniadichloridocobalt(|||), in this compound the oxidation state of cobalt is +3, which means its configuration will become [Ar] 4s⁰ 3d⁶

^{So now the hybridisation of cobalt will d²sp³}

^{^{Gaurav Singh}}

^{^{askIITians Faculty}}

^{^{BS-MS, IISER bhopal}}

shubhangi modi · Answer

so u are doing hybridization first by strong ligand and than by weak ligand. ok fine.thanks

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

[Co(cl)2(NH3)4]^(+) ..... tetraammoniadichloridocobalt(|||) is a AB6L type of molecule , shape is octahedron. But how?? plz explain the hybridisation of the compound

[Co(cl)2(NH3)4]^(+) ..... tetraammoniadichloridocobalt(|||) is a AB6L type of molecule , shape is octahedron. But how?? plz explain the hybridisation of the compound

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Organic Chemistry

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

[Co(cl)2(NH3)4]^(+) ..... tetraammoniadichloridocobalt(|||) is a AB6L type of molecule , shape is octahedron. But how?? plz explain the hybridisation of the compound

[Co(cl)2(NH3)4]^(+) ..... tetraammoniadichloridocobalt(|||) is a AB6L type of molecule , shape is octahedron. But how?? plz explain the hybridisation of the compound

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Organic Chemistry

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship