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`        Calculate the mass of urea required in making 2.5kg of 0.25molal aqueous solution`
7 months ago

Arun
23485 Points
```							 Molality(m) = 0.25 mol kg-1mass of the solution = 2.5 kg = 2500 gTo find,mass of urea required = ? [Molality = given mass of solute/molar mass × 1000/mass of the solvent (in g)] molar mass=(14+2+12+16+14+2) =60 g mol-1 Let x be the mass of urea required.mass of the solvent = (2500-x)substituting the values,0.25=x/60 ×1000/(2500-x)(2500-x)=x/60 ×1000/0.25(2500-x)=200x/32500=203x/3x=7500/203x=36.946 g
```
7 months ago
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• Test paper with Video Solution
• Mind Map
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• NCERT Solutions
• Discussion Forum
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