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Calculate is the oxidation number of Fe in [Fe(CN)6]4-
Let the oxidation number of Fe be XHere oxidation number on CN = -1For [Fe(CN)6]4- X + 6 (-1) = -4∴ X = +2 Hence the oxidation state/ number of inner Fe is +2
Let the oxidation number of Fe be X
Here oxidation number on CN = -1
For [Fe(CN)6]4-
X + 6 (-1) = -4
∴ X = +2
Hence the oxidation state/ number of inner Fe is +2
The total charge is -4.The O. State of CN is -1.Therefore the OS of Fe+ OS of(CN)×6 = -4.Therefore OState of Fe is +2.
Since we consider fe as x.We know that Oxidation number of CN is -1Now, x+(-1)6=-4And solve it .....We get Oxidation state of Fe is +2
Let OS of Fe be x...then....X + (-1)6 = -4...X = -4 + 6 …So x = +2...So oxidation state of iron Fe in the complex is +2
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