Arrange the following compounds in order of increasing dipole moment.Toluene(I)m – dichlorobenzene(II)O – dichlorobenzene(III)p – dichlorobenzene(IV)(a) I(d) IV(c) IV(d) IV

(b). Dipole moment of p – dichlorobenzene is zero because of symmetrical structure. o- and m-dichlorobenzene have higher dipole moments than toluene due to high electronegativity of chlorine than –CH₃ group. Further, to the o-dichlorobenzene has higher dipole moment due to lower bond angle than the m-isomer. Hence, the order of increasing dipole moment is :

P –dichlorobenzene (IV) < toluene (I)

Dear Student,
Please find below the solution to your problem.

Dipole moment of p – dichlorobenzene is zero because of symmetrical structure. o- and m-dichlorobenzene have higher dipole moments than toluene due to high electronegativity of chlorine than –CH3 group. Further, to the o-dichlorobenzene has higher dipole moment due to lower bond angle than the m-isomer. Hence, the order of increasing dipole moment is :
P –dichlorobenzene (IV) < toluene (I)
< m –dichlorobenzene (II) < o –dichlorobenzene (III)

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