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Arrange the following compounds in order of increasing dipole moment. Toluene(I) m – dichlorobenzene(II) O – dichlorobenzene(III) p – dichlorobenzene(IV) (a) I (d) IV (c) IV (d) IV

Arrange the following compounds in order of increasing dipole moment.
Toluene(I)                                         m – dichlorobenzene(II)
O – dichlorobenzene(III)            p – dichlorobenzene(IV)
(a) I
(d) IV
(c) IV
(d) IV

Grade:11

2 Answers

Kevin Nash
askIITians Faculty 332 Points
9 years ago

(b). Dipole moment of p – dichlorobenzene is zero because of symmetrical structure. o- and m-dichlorobenzene have higher dipole moments than toluene due to high electronegativity of chlorine than –CH3 group. Further, to the o-dichlorobenzene has higher dipole moment due to lower bond angle than the m-isomer. Hence, the order of increasing dipole moment is :

P –dichlorobenzene (IV) < toluene (I)

< m –dichlorobenzene (II) < o –dichlorobenzene (III)
Rishi Sharma
askIITians Faculty 646 Points
2 years ago
Dear Student,
Please find below the solution to your problem.

Dipole moment of p – dichlorobenzene is zero because of symmetrical structure. o- and m-dichlorobenzene have higher dipole moments than toluene due to high electronegativity of chlorine than –CH3 group. Further, to the o-dichlorobenzene has higher dipole moment due to lower bond angle than the m-isomer. Hence, the order of increasing dipole moment is :
P –dichlorobenzene (IV) < toluene (I)
< m –dichlorobenzene (II) < o –dichlorobenzene (III)

Thanks and Regards

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