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Grade: 12th pass
        
An optically active alcohol A (C6H10O) absorbs 2 moles of H2 per mole of A upon hydrogenation and gives compound B which does not show  optical activity .What are A ,B.?      
 
 
 
 
I m not getting how to know the structure of alcohol to proceed for solution
 
3 months ago

Answers : (3)

Arun
23013 Points
							
Compound A has following feature:
1) one asymmetric carbon
2) one OH group
3) ​one triple bond (as it is absorbing 2 mole of H2 for complete hydrogenation)
4) The C bearing OH group does not contain any H that is why compound B is resistant to oxidation.
 
3 months ago
Vikas TU
9484 Points
							
Compound A is unsaturated monohydric alcohol and it has either two C= C bonds or one triple bond. Compound A is optically active and after hydrogenation optically inactive compound 'B' is obtained which is not oxidised with CrO3. Hence, in it  -OH group is attached with tertiary C-atom i.e. it is a tertiary alcohol.
3 months ago
Devik Bansal
13 Points
							
Compound A is unsaturated monohydric alcohol and it has either two C=C bonds or one triple bond.
Compound A is optically active and after hydrogenation optically inactive compound B is obtained which is not oxidise with CrO3. Hence in it -OH group is attached  With tertiary C atom i.e., it is a tertiary alcohol
3 months ago
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