Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 6
An enantiomerically pure acid is treated with a racemic mixture of an alcohol having one chiral carbon. The ester formed will be
a. Optically active mixture
b. Pure enantiomer
c. Meso compound
d. Racemic mixture
3 years ago

Answers : (3)

Kevin Nash
askIITians Faculty
332 Points

a) The optically active acid will react with d and l forms of alcohol present in the racemie mixture at different rates to form two diastereomers in unequal amounts leading to optical activity of the product.

3 years ago
11 Points
							Sorry, but above solution is incorrect.We hope to get a correct solution by iitians,!¡!!!!!!!!!!!!!¡!!!!!!!!!!!!!!!!!!!!?!!!??!+(+;!;!!!;;:;!;:;;!!!!!!!!!!!!¡
one year ago
13 Points
							The answer above is correct as the acid form will be same nd have equal chiral carbon nd will be optically active
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution

Course Features

  • 70 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details