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amanat Grade: 6
        
An enantiomerically pure acid is treated with a racemic mixture of an alcohol having one chiral carbon. The ester formed will be
a. Optically active mixture
b. Pure enantiomer
c. Meso compound
d. Racemic mixture
3 years ago

Answers : (3)

Kevin Nash
askIITians Faculty
332 Points
										

a) The optically active acid will react with d and l forms of alcohol present in the racemie mixture at different rates to form two diastereomers in unequal amounts leading to optical activity of the product.

3 years ago
Krishnapal
11 Points
										Sorry, but above solution is incorrect.We hope to get a correct solution by iitians,!¡!!!!!!!!!!!!!¡!!!!!!!!!!!!!!!!!!!!?!!!??!+(+;!;!!!;;:;!;:;;!!!!!!!!!!!!¡
										
9 months ago
Prachi
13 Points
										The answer above is correct as the acid form will be same nd have equal chiral carbon nd will be optically active
										
9 months ago
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