Organic Chemistry> An enantiomerically pure acid is treated ...

An enantiomerically pure acid is treated with a racemic mixture of an alcohol having one chiral carbon. The ester formed will be
a. Optically active mixture
b. Pure enantiomer
c. Meso compound
d. Racemic mixture

amanat , 11 Years ago

Grade 6

4 Answers

Kevin Nash

a) The optically active acid will react with d and l forms of alcohol present in the racemie mixture at different rates to form two diastereomers in unequal amounts leading to optical activity of the product.

Last Activity: 11 Years ago

Krishnapal

Sorry, but above solution is incorrect.We hope to get a correct solution by iitians,!¡!!!!!!!!!!!!!¡!!!!!!!!!!!!!!!!!!!!?!!!??!+(+;!;!!!;;:;!;:;;!!!!!!!!!!!!¡

Last Activity: 8 Years ago

Prachi

The answer above is correct as the acid form will be same nd have equal chiral carbon nd will be optically active

Last Activity: 8 Years ago

Kartik

The enatiomerically pure acid or optically active acid will react with both the forms (d and l) of the alcohol in the racemic mixture to form isomeric pair of esters. In each isomer the configuration of the chiral center(carbon) remains the same , so the mixture will be optically active.

Last Activity: 7 Years ago