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Grade: 12

                        

A constant force of magnitude 50N is applied ona body of mass 10kg moving initially with a speed of 10 m s -1 against the direction of motion. how long will it take the body to come to rest?

2 years ago

Answers : (1)

Yadesh
13 Points
							
Retardation produced in body is ==Force÷mass=50÷10=5m/s^2 
So now by eqn--
v=u+at
0=10+(--5)t
Or 10=5t
Hence time=2sec is answer             
2 years ago
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