badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

A carnot engine exhausting heat to sink at 27 0 c has an effciency of 25% . it must be taking heat from the source at 673 0 c 327 0 c 227 0 c 127 0 c

2 years ago

Answers : (1)

Arun
25211 Points
							

Taking the Sink Temperature(T2) = 27 degree celsius = 300 kelvin

Efficiency(eta) be 25% = .25

Source Temperature(T1) = ?

Efficiency= (T1 - T2) / T1

Efficiency= 1 -T2/T1

T2/T1 = 1 - Efficiency

T1 = T2/(1 - Efficiency)

T1= 300/(1-.25)

T1 = 400 kelvin = 127 degree celsius

2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 70 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details