Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
A carnot engine exhausting heat to sink at 27 0 c has an effciency of 25% . it must be taking heat from the source at 673 0 c 327 0 c 227 0 c 127 0 c
Taking the Sink Temperature(T2) = 27 degree celsius = 300 kelvinEfficiency(eta) be 25% = .25Source Temperature(T1) = ?Efficiency= (T1 - T2) / T1Efficiency= 1 -T2/T1T2/T1 = 1 - EfficiencyT1 = T2/(1 - Efficiency)T1= 300/(1-.25)T1 = 400 kelvin = 127 degree celsius
Taking the Sink Temperature(T2) = 27 degree celsius = 300 kelvin
Efficiency(eta) be 25% = .25
Source Temperature(T1) = ?
Efficiency= (T1 - T2) / T1
Efficiency= 1 -T2/T1
T2/T1 = 1 - Efficiency
T1 = T2/(1 - Efficiency)
T1= 300/(1-.25)
T1 = 400 kelvin = 127 degree celsius
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -