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The rate law for substitution of 2-bromobutane with HO --- in 75% ethanol 25% water at 30 degrees centigrade is Rate = 3.2 x 10 ---5 [2-bromobutane][HO --- ] 1.5 x 10 ---6 [2-bromobutane] What % of reaction takes place by SN2 when a) [HO --- ] = 1 M b) [HO --- ] = 0.001 M

The rate law for substitution of 2-bromobutane with HO--- in 75% ethanol 25% water at 30 degrees centigrade is


Rate = 3.2 x 10---5[2-bromobutane][HO---] 1.5 x 10---6[2-bromobutane]


What % of reaction takes place by SN2 when


a) [HO---] = 1 M


b) [HO---] = 0.001 M

Grade:12

1 Answers

Arun
25758 Points
2 years ago
The rate law for substitution of 2-bromobutane with HO --- in 75% ethanol 25% water at 30 degrees centigrade is Rate = 3.2 x 10 ---5 [2-bromobutane][HO --- ] 1.5 x 10 ---6 [2-bromobutane]

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