1. Calculate the useful work of the reaction
Ag(s) + Cl2(g) AgCl(s) Given EoCl2/Cl– = + 1.36 V
EoAgCl/Ag,Cl– = 0.22 V
if PCl2 = 1 atm and T = 298 K

(a) 110 kJ/mol
(b) 220 kJ/mol
(c) 55 kJ/mol
(d) 1000 kJ/mol

Question

SRUTI · Answer

DECREASE IN FREE ENERGY OF THE SYSTEM =ELECTRICAL WORKDONE =nE0F WHERE n is no of electrons participating in the reacn E0is emf of cell & F IS FARADAY CONSTANT sub values work done=2×96450×0.22=42.84 kJ/mol then it will be around 55kj/mol

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1. Calculate the useful work of the reaction Ag(s) + Cl2(g) AgCl(s) Given EoCl2/Cl– = + 1.36 V EoAgCl/Ag,Cl– = 0.22 V if PCl2 = 1 atm and T = 298 K (a) 110 kJ/mol (b) 220 kJ/mol (c) 55 kJ/mol (d) 1000 kJ/mol

1. Calculate the useful work of the reaction
Ag(s) + Cl2(g) AgCl(s) Given EoCl2/Cl– = + 1.36 V
EoAgCl/Ag,Cl– = 0.22 V
if PCl2 = 1 atm and T = 298 K

(a) 110 kJ/mol
(b) 220 kJ/mol
(c) 55 kJ/mol
(d) 1000 kJ/mol

1 Answers

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1. Calculate the useful work of the reaction Ag(s) + Cl2(g) AgCl(s) Given EoCl2/Cl– = + 1.36 V EoAgCl/Ag,Cl– = 0.22 V if PCl2 = 1 atm and T = 298 K (a) 110 kJ/mol (b) 220 kJ/mol (c) 55 kJ/mol (d) 1000 kJ/mol

1. Calculate the useful work of the reaction Ag(s) + Cl2(g) AgCl(s) Given EoCl2/Cl– = + 1.36 V EoAgCl/Ag,Cl– = 0.22 V if PCl2 = 1 atm and T = 298 K (a) 110 kJ/mol (b) 220 kJ/mol (c) 55 kJ/mol (d) 1000 kJ/mol

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1. Calculate the useful work of the reaction
Ag(s) + Cl2(g) AgCl(s) Given EoCl2/Cl– = + 1.36 V
EoAgCl/Ag,Cl– = 0.22 V
if PCl2 = 1 atm and T = 298 K

(a) 110 kJ/mol
(b) 220 kJ/mol
(c) 55 kJ/mol
(d) 1000 kJ/mol