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cis-2-butene is heated to a high temperature.The heat absorbed is about 167.2kj/mole.On cooling a mixture of cis-2-butene and trans-2-butene is obtained.Draw the steps to explain in the formation of the mixture from the cis isomer

cis-2-butene is heated to a high temperature.The heat absorbed is about 167.2kj/mole.On cooling a mixture of cis-2-butene and trans-2-butene is obtained.Draw the steps to explain in the formation of the mixture from the cis isomer

Grade:9

1 Answers

Nandakumar UK
37 Points
7 years ago

Probably the pi bond is broken which leads to a bifree radical with free rotation about C-C single bond. If rebonding takes place after a 180 degree rotation, the product would be trans. other possibilities can also be thought about :)

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