The solution containing 4.0 g of PVC in one litre of dioxane was found to have O.P. of 6.0 × 10⁻⁴ atm. at 300 K. The mol. mass of polymer is

        (A)    6.4 × 10²

        (B)    3.0 × 10²

        (C)    1.6 × 10⁵

(D)    5.6 × 10⁴

Question

The solution containing 4.0 g of PVC in one litre of dioxane was found to have O.P. of 6.0 × 10⁻⁴ atm. at 300 K. The mol. mass of polymer is

(A) 6.4 × 10²

(B) 3.0 × 10²

(C) 1.6 × 10⁵

(D) 5.6 × 10⁴

Deepak Patra · Answer

W 2 = 4g V = 1000 mL = 11 = 6.0 &times; 10 &minus;4 atm T = 300 K R = 0.0821 It atm K &minus;1 mol &minus;1 M 2 V = W 2 RT = 16.42 &times; 10 4 M 2 = 1.6 &times; 10 5

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The solution containing 4.0 g of PVC in one litre of dioxane was found to have O.P. of 6.0 × 10 −4 atm. at 300 K. The mol. mass of polymer is (A) 6.4 × 10 2 (B) 3.0 × 10 2 (C) 1.6 × 10 5 (D) 5.6 × 10 4

The solution containing 4.0 g of PVC in one litre of dioxane was found to have O.P. of 6.0 × 10⁻⁴ atm. at 300 K. The mol. mass of polymer is

        (A)    6.4 × 10²

        (B)    3.0 × 10²

        (C)    1.6 × 10⁵

(D)    5.6 × 10⁴

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