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since two aldehydes participate along with oh therefore the order of reaction is three
overall the reaction is a third-order reaction. It is second order wrt aldehyde and first order wrt base:-
rate = k[RCHO]2[OH]
however at very high base concentration a second path (k'') becomes important and it becomes second order wrt base:-
rate = k[RCHO]2[OH-] + k''[RCHO]2[OH-]2
for exams generally consider the first argument i.e. it is a third order reaction
vikash kumar
Btech. IIT-Delhi
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