given no of optical isomer i.e. pentan-2,3,4-triol
shahid sohail , 12 Years ago
Grade
Organic Chemistry> given no of optical isomer i.e. pentan-2,...
1 Answers
Aarti Gupta
There will be 4 optical isomers of this compound:-
There will be two chiral centres which seem to give 2 × 2 × 2
combinations. However, only 4 isomers are possible.
The (2R, 4R) and (2S, 4S) forms are enantiomers of each other.(2R,4R)-pentane-2,3,4-triol (2S,4S)-pentane-2,3,4-triol
There are also two meso forms:
(2R,3s,4S)-pentane-2,3,4-triol
(2R,3r,4S)-pentane-2,3,4-triol
Any other form that can be drawn is actually identical to one of these.
Thanks & regard
Aarti Gupta
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