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given no of optical isomer i.e. pentan-2,3,4-triol

given no of optical isomer i.e. pentan-2,3,4-triol

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1 Answers

Aarti Gupta
askIITians Faculty 300 Points
7 years ago
There will be 4 optical isomers of this compound:-

There will be two chiral centres which seem to give 2 × 2 × 2 combinations. However, only 4 isomers are possible.

The (2R, 4R) and (2S, 4S) forms are enantiomers of each other.(2R,4R)-pentane-2,3,4-triol (2S,4S)-pentane-2,3,4-triol

There are also two meso forms:

(2R,3s,4S)-pentane-2,3,4-triol

(2R,3r,4S)-pentane-2,3,4-triol

Any other form that can be drawn is actually identical to one of these.

Thanks & regard

Aarti Gupta

askiitians Faculty

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