log[H+]=4.15 then how what is the value of [H+] and how to calculate that? please explain your answer quickly.

log[H+]=4.15 ie log₁₀[H+]=4.15

taking antilog both sides;

antilog log₁₀[H+]=antilog 4.15

so,

[H+]=10^(4.15)

using log table we get 

[H+]=10^(4.15)=14125.375

it is important to note anti log is taken to remove log . base should be appropriate while using logarithemic functions.

Take log of 4.15.... You will get the answer....

Believing its log to the base 10 using Log_a(x)= y then x=a^y

hence [H] = 10^4.15 this thing is called antilog 

if allowed a log book look up the value of .15 in antilog portion ,say it is 1234 then [H] = 1.234 x 10^4

dear friend ,

                          if you got any type antilog sums one tip you have to learn that is

                                 antilog (x) = 10^x

                this is useful for any problem ok

                  and solved this type of questions. good luck