Organic Chemistry> acidity...

decreasing order of basic strength in c6h5nh2 , (c6h5)2 nh ,ch3nh2 , nh3 is ? please answer it i will approve definitely

Revanth - - , 13 Years ago

Grade 11

4 Answers

Varun Harnathka

In decreasing order of basic strength in gas phase: C2H5NH2, (C2H5)2NH, (C2H5)3N and NH3 In gas phase there is no hydrogen bonding , therefore stabalisation due to hydrogen bonding is not there. Therfore the only effect to determine the strength is the inductive effect.The +I effect increases with increase in the alkyl group.Therefore the basic strength will be the highest in (C2H5)3N and least in NH3. Therefore the decreasing order of basic strength in gas phase will be (C2H5)3N > (C2H5)2NH > C2H5NH2 > NH3.

Last Activity: 13 Years ago

Mujahid Ahmed

Basic Strength

CH3-NH2 > NH3 > Ph-NH2 > (Ph)2 Nh

Basic strength is the ability to donate lone pair. Due to Inductive effect by Ch3, Negative charge density on N increases thus lone pair giving tendency increases. When benzene ring is attached with Nitrgen, it''s lone pair resonates and is not available for free donation, thus low basic strength. In 2 phenyl groups, more resonance is there and hence even lower Basic strength .

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Last Activity: 13 Years ago

Maithil Patel

)

N(CH

)

Due to the −I effect of C

group, the electron density on N-atom C

−NH

is lower than that on the N-atom (C

)

NH . But in case of C

N(CH

)

, two CH

group attached with N atom which increases the electron density on N-atom and in CH

−NH

only +I effect of methyl group increases the basicity of the compound

Last Activity: 4 Years ago

Maithil Patel

see ammonia is least basic of all.as it have no alkyl group then talking about methanamine which is more basic than ammonia as it have the alkyl group later aniline which have nh2 group which is the electron donating species as a result it is more basic than ammonia and the methanamine and due steric hinderence the phenyl aniline is most basic

Last Activity: 4 Years ago