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Arragne the following on increasing order of ester formation.
1. PhCH2CH2OH
2. PhCH(OH)CH2
3. T -CH2OH where T stands for O-Methyl Toulene
I think .......
3>1>2....
Based on neucleophilicity........................
The answer is absolutely correct. Pls further elaborate d answer.
Ester formation has attack of neucleophile as its R.D.S........
So a better neucleophile gives, faster rate & here only inductive effect is predominant,
As, Ph is a -I group, it decreases the electron density on O..........
So the best Nu is 3......
In 1 & 2, 2 has OH closer to Ph, so more -I effect, and hence, 1 is better Nu than 2........................
So, 3>1>2
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