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Arragne the following on increasing order of ester formation. 1. PhCH2CH2OH 2. PhCH(OH)CH2 3. T -CH2OH where T stands for O-Methyl Toulene

Arragne the following on increasing order of ester formation.


1. PhCH2CH2OH


2. PhCH(OH)CH2


3. T -CH2OHΒ  where T stands forΒ  O-Methyl Toulene


Β 

Grade:11

3 Answers

Shashwat Tiwari
20 Points
9 years ago

I think .......

3>1>2....

Based on neucleophilicity........................

Swapnil Saxena
102 Points
9 years ago

The answer is absolutely correct. Pls further elaborate d answer.

Shashwat Tiwari
20 Points
9 years ago

Ester formation has attack of neucleophile as its R.D.S........

So a better neucleophile gives, faster rate & here only inductive effect is predominant,

As, Ph is a -I group, it decreases the electron density on O..........

So the best Nu is 3......

In 1 & 2, 2 has OH closer to Ph, so more -I effect, and hence, 1 is better Nu than 2........................

So, 3>1>2

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