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How does C2H5ONa helps in the reduction of imines to form alkanes during the Wolff Kishners process???
Step-1 Addition reaction
CH3CH=NR + 2HNNH2 → CH3CH-NHR
|
HNNH2
Step- 2 Deprotonation
CH3CH-NHR CH3CH-NHR
| + 2C2H5ONa → | + 2C2H5OH + 2Na+
HNNH2 N=NH
Step- 3 Deprotonation
CH3CH-NHR
| + C2H5ONa + 2H+ → CH3CH3 + N2 + RNH¯Na+ + C2H5OH
N=NH
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