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the hydrated chloride of divalent metl loses 14.73%(by weight) of its mass by dehydration. if one mole of hydrated salt contain 2 moles of hydration,calculate weight% of chlorine in hydrated salt..

shyam sundar , 14 Years ago
Grade 11
anser 1 Answers
pranshu aggarwal

Dear Shyam here is the solution,

 

 

According to question, salt should be (XCl2).2H2O
 

Now, consider molecular mass of salt be 'M'
 

 

After dehydration 14.73% weight is lossed that is the weight of water. Hence,

(2*18/M)*100=14.73 (where 18 is mol. mass of H2O)

By solving equation, you will get M=244.4gm

Hence % of chlorine would be

(2*35.5/244.4)*100= 29.03%

 

29.03% is the Ans.

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