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a mixture of 2g each of MgSO 4 &CuSO 4 is dissolved in water and treated with excess of barium chloride solution. calculate weight of BaSO 4 precipitated..


a mixture of 2g each of MgSO4 &CuSO4 is dissolved in water and treated with excess of barium chloride solution. calculate weight of BaSO4 precipitated..



Grade:11

1 Answers

Arun
25750 Points
3 years ago
As we know that,
No. of moles= 
mol. wt.
wt.
​ 
 
Now,
Wt. of Mg=6g
Mol. wt. of Mg=24g
No. of moles of Mg in 6g= 
24
6
​ 
 =0.25 moles
Mg+H 
2
​ 
 SO 
4
​ 
 ⟶MgSO 
4
​ 
 +H 
2
​ 
 
from the above reaction,
1 mole of magnesium sulphate is formed when 1 mole of magnesium reacts.
Therefore,
0.25 mole of magnesium sulphate is formed when 0.25 mole of magnesium reacts.
Now,
Mol. wt. of MgSO 
4
​ 
 =120g
Therefore,
Wt. of 0.25 moles of MgSO 
4
​ 
 =0.25×120=30g
Hence 30g of magnesium sulphate is formd when 6g of magnesium reacts with excess of H 
2
​ 
 SO 
4
​ 
 .

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