Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
0.2g of anhydrous organic acid gave on combustion 0.04g water and 0.195gof carbon di oxide. The acid is found to be dibasic and 0.5g of its silver salt leaves on ignition 0.355g silver. The molecular formula of the compound is
Hi Pallavi,
0.5 g silver salt-------------0.355 g silver--------------0.145g
R(COOAg)2 Ag R(COO-)2
0.355/108----no of moles of Ag
0.355/216----no of moles of R(COO-)2
Mol. Wt. of R(COO-)2 is 0.145/(0.355/216) = 88
Mol. Wt. of R(COOH)2 is 88+2 = 90
0.2 g of Acid------0.2/90= 0.002222 moles
0.002222 moles acid-------- 0.04*2/18 = 0.004444 moles H--------0.195/44 = 0.00444 moles of C
1 mole acid------2 moles H-------2 moles C
(COOH)2 is the Molecular formula of the Organic acid.
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !