A compound of carbon,hydrogen and nitrogen contains the elements in the ratio of 18:2:7.Its empirical formula will be

Let the compound be C_aH_bN_c

and stomic wts. are 12,1,14 respectiveky for C,H,N

12a/(12a+b+14c) = 18/27   ... (1)

b/(12a+b+14c) = 2/27        ... (2)

14c/(12a+b+14c) = 14/27   ... (3)

on dividing 1 and 3 , we have ... a = 3c

on dividing 2 and 3 , we have ... b = 4c

so, the empirical formula is C₃H₄N

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Ramesh  
IIT Kgp - 05 batch

hi,

  so , empirical formula of compound would be =

                                                                 = C₃ H₄ N