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A compound of carbon,hydrogen and nitrogen contains the elements in the ratio of 18:2:7.Its empirical formula will be
Let the compound be CaHbNc
and stomic wts. are 12,1,14 respectiveky for C,H,N
12a/(12a+b+14c) = 18/27 ... (1)
b/(12a+b+14c) = 2/27 ... (2)
14c/(12a+b+14c) = 14/27 ... (3)
on dividing 1 and 3 , we have ... a = 3c
on dividing 2 and 3 , we have ... b = 4c
so, the empirical formula is C3H4N
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hi,
elements ratio P =ratio/corresponding atomic wt P divided by least no. in previous column Ratio of atoms in empirical formula C 18 18/12 = 1.5 1.5/0.5 =3 3 H 2 2/1 = 2 2/ 0.5 = 4 4 N 7 7 / 14 = 0.5 .5 /.5 = 1 1
elements
ratio
P =ratio/corresponding atomic wt
P divided by least no. in previous column
Ratio of atoms in empirical formula
C
18
18/12 = 1.5
1.5/0.5 =3
3
H
2
2/1 = 2
2/ 0.5 = 4
4
N
7
7 / 14 = 0.5
.5 /.5 = 1
1
so , empirical formula of compound would be =
= C3 H4 N
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