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what is the product obtained???
(CH3)2CH=CH(CH3)2 + HBr:
plz reply asap!
its a symmetrical alkene..it will add on to the compound across the double bond.
the product will be
(ch3)2ch2-chbr(ch3)2. or the other way round..the compund 'll be the same
Br wud be added to any one of the doubly bonded carbon atoms as it is a symmetrical alkene
As per markownikoff rule, "whenever there is an unsymmetrical reagent attacks an unsymmtrical alkene; then negative part of reagent goes to that part of an alkene which has least number of hydrogen atoms ".
Since here we have a symmetrical alkene ,so the ¶ bond can be shifted on any side.
Note : 1. In this problem, even peroxide does not brings any change in the product .
2. But had it been an unsymmetrical alkene ,then the product would be different
in presence of a peroxide (kharasch Effect).
3. Peroxide effect fails in case of HCL and HI.
Check this reply!!!!!!!
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