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This question relates to dissociation of Methanoic Acid (HCOOH) to Methanoate ion (HCOO - ) in H 2 O Solvent. HCOOH + H 2 O -> HCOO - + H 3 O + A book says there is delocalisation in both methanoic acid and methanoate ion but it will be ineffective for the acid, as resonance in methanoic acid involves "separation of charge" , so it will discourage the recombination of proton with the anion formed and equilibrium is shifted to the right side. How charge separation resists recombination of proton ?? this is related to resonance affecting acidity of methanoic acid.

This question relates to  dissociation of Methanoic Acid (HCOOH) to Methanoate ion (HCOO-) in H2O Solvent.

     HCOOH + H2O -> HCOO- + H3O+

A book says there is delocalisation in both methanoic acid and methanoate ion but it will be ineffective for the acid, as resonance in methanoic acid involves "separation of charge" , so it will discourage the recombination of proton with the anion formed and equilibrium is shifted to the right side.

How charge separation resists recombination of proton ??

this is related to resonance affecting acidity of methanoic acid.

Grade:

1 Answers

Arun
25763 Points
one year ago
HCOOH + H2O º. HCOO- + H3O+ formic acid water formate ion hydronium ion. Acid Strength. Its equilibrium position lies far to the right. (HNO3). Yields a weak conjugate base. (NO3. −).

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