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10) CH 3 CHO + HCN " src="http://equations.ipractice.in/cgi-bin/mimetex.cgi?%5Cdisplaystyle%5Cto" alt="" width="16" height="9" /> CH 3 CH(OH)CN. The reaction produces a chiral centre. The product will be (A) Meso-compound (B) Dextro rotatory (C) Racemic mixture (D) Leavo-rotatory









10)




CH3CHO + HCN  CH3CH(OH)CN. The reaction produces a chiral centre. The product will be





(A)  

Meso-compound





(B)  

Dextro rotatory





(C)  

Racemic mixture





(D)  

Leavo-rotatory




Grade:12

3 Answers

abhishek ganguly
8 Points
11 years ago

When the product develops a chiral centre, always the product exists in the form of a racemic mixture.

therefore answer is (c)

Sanjeev Malik IIT BHU
101 Points
11 years ago

attack of HCN (H+ + CN-) forms cation of CH3CHO as CH3C+(OH)H. this cation is planar and thus CNcan attack from both sides of the plane(up and down). thus mixture contains enantiomers in equal amount and it becomes racemic mixture with optically INACTIVE behaviour as a whole.

although individually CH3CH(OH)CN  is optically active compound.

NIKHIL VIRDHI
14 Points
11 years ago

carbonyl carbon is planar in nature hence the cyanide ion can attack it either above the plane or below the plane resulting in formation of two compounds opposite in conf. or a racemic mixture

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