10) CH3CHO + HCN src=http://equations.ipractice.in/cgi-bin/mimetex.cgi?%5Cdisplaystyle%5Cto alt= width=16 height=9 /> CH3CH(OH)CN. The reaction produces a chiral centre. The product will be (A) Meso-compound (B) Dextro rotatory (C) Racemic mixture (D) Leavo-rotatory

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10)

CH₃CHO + HCN src=http://equations.ipractice.in/cgi-bin/mimetex.cgi?%5Cdisplaystyle%5Cto alt= width=16 height=9 /> CH₃CH(OH)CN. The reaction produces a chiral centre. The product will be

(A)
Meso-compound

(B)
Dextro rotatory

(C)
Racemic mixture

(D)
Leavo-rotatory

Geoffrey Richards , 15 Years ago

Grade 12

3 Answers

abhishek ganguly

When the product develops a chiral centre, always the product exists in the form of a racemic mixture.

therefore answer is (c)

Last Activity: 14 Years ago

Sanjeev Malik IIT BHU

attack of HCN (H⁺ + CN^-) forms cation of CH₃CHO as CH₃C⁺(OH)H. this cation is planar and thus CN^-can attack from both sides of the plane(up and down). thus mixture contains enantiomers in equal amount and it becomes racemic mixture with optically INACTIVE behaviour as a whole.

although individually CH₃CH(OH)CN is optically active compound.

Last Activity: 14 Years ago

NIKHIL VIRDHI

carbonyl carbon is planar in nature hence the cyanide ion can attack it either above the plane or below the plane resulting in formation of two compounds opposite in conf. or a racemic mixture

Last Activity: 14 Years ago