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How do i get the bond order of benzene molecule ...???
Any specific formula for finding the ans for this & for other organic compounds???
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The bond order of benzene is equal to 1/2 * ( the number of electrons in the bonding orbital - the number of electrons in the antibonding orbital). If you have a bond order of 1 then you will have a single bond (aka sigma). If you have a bond order of 2 then you will have a double bond (aka 1 sigma and 1 pi). Because the electrons resonate throughout the benzene ring and the bonds are always shifting (that's why you see a benzene ring with a circle in it usually) then the bond order is 1.5.
Please approve
two different types of bond are present in benzene.
C-C bond order is 3/2 = 1.5
whereas C-H bond order is 1.
bond order is No.of bonds/no.of centers.
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