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this reaction will peoceed through SN1 path
first step is protonation(H+ from HBr) & formation of O+H2 , this group is highly strong leaving group ...
now , carbocation formation takes place & reactivity is governed on the basis of carbocation stablity ...
most stable III , due to presence ofO-CH3 group , this will disperse +ve charge on carbon ...
then I , coz here no electron withdrawing groups ...
then IV , highly unstable due to EW effect of Br ..
then II , highly unstable coz EW (inductive as well as resonance) effect of NO2
option A) is correct
option-A is correct...
bcoz -NO2 group increases the acidity of p-nitrobenzylalcohol more than of p-bromobenzylalcohol by -Br group while -OCH3 group decreases the acidity of p-methoxybenzylalcohol than that of benzylalcohol...
decreasing order of acidity is.......-NO2>-Br>-H>-OCH3
therefore, decreasing order of reactivity is......-OCH3>-H>-Br>-NO2
So, option A is correct....
approve if u like....
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