| A) | I and II |
| B) | II and III |
| C) | III and IV |
| D) | I and IV |
Can u help me here ...i think the ans is B since aromatic compounds have a (4n+2)pi electrons in their ring according to the Huckel's rule but is there any other rule so as to find the anti - aromatic compound and if so pls specify....
Is my ans right??? If not pls give the right ans with the apt explanation
Geez..Thank You
Approved Tutor Answer15 Years agoI think Option C is correct..Coz III has got only 4 pi-electrons..So Huckel's rule disobeyed... N IV obviously
Compound II has no pi electrons! So no need to consider..
Anyway right option is either C or D.
Approved Tutor Answer15 Years agosurely option C is correct ...
for anti aeromatic - all carbons should be in conjugation & should not follow (4n+2) pi ectron rule ...
I,II are both aeromatic but III,IV both anti aeromatic coz all atoms are in conjugation but system has
4 pi electrons from 2 double bonds & thus violates (4n+2) rule ..
4n+2 rule means - for n =0, 1,2 pi electrons are 2,6,10 .....so on
number of pi electrons should be 2 , 6 , 10 ....
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