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In the preparation of alkanes by the reduction of alkyl halides, we observe the following reaction:
R-X + 2H --------> R-H + X2
X=Halogen, R=Alkyl group
Can you explain the mechanism of this reaction?
R-X + 2H --------------> R-H + X2
R-X , H-H bond is cleaved homolatically by using light (high temperature) to form free radicals...
R-X = R. + X.
H2 = H. + H.
R.+R. = R-R
X. + X. = X2
R.+H. = R-H
this reaction is free radical substitution ...
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